a) Xét \(\Delta KFH\) và \(\Delta KEF\) có:
\(\widehat{K}\) chung ; \(\widehat{KFH}=\widehat{KEF}=\left(\frac{1}{2}sđcungHF\right)\)
=> \(\Delta KFH\) đồng dạng \(\Delta KEF\)
=>\(KF^2=KE.KH\) (1)
b) Vì: EG//MF(gt) => \(\widehat{KMH}=\widehat{MGE}\)
Mà: \(\widehat{MGE}=\widehat{MEH}\left(=\frac{1}{2}sđcungHE\right)\)
=> \(\widehat{KMH}=\widehat{MEH}\)
=> \(\Delta KHM\) đồng dạng \(\Delta KME\)
=> \(\frac{KM}{KE}=\frac{KH}{KM}\Rightarrow KM^2=KE.KH\) (2)
Từ (1)(2)=>đpcm