ab(c^2+d^2)=ab.c^2+ab.d^2=(a.c)(b.c)+(a.d)(b.d)
cd(a^2+b^2)=cd.a^2+cd.b^2=(c.a)(d.a)+(c.b)(d.b)
(a.c)(b.c)+(a.d)(b.d)=(c.a)(d.a)+(c.b)(d.b) vì mỗi vế đều bằng nhau
*chững minh (a^2+b^2)/(c^2+d^2)=(a+b)^2/(c+d)^2
ta có vì a/b=c/d=>a/c=b/d=>(a+b)/(c+d)=a/c=b/d=>(a+b)^2/(c+d)^2=
a^2/c^2=b^2/d^2=>(a+b)^2/(c+d)^2=(a^2+b^2)/(c^2+d^2)