\(2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O\)
\(\rightarrow nNaOH=\dfrac{8}{40}=0,2mol\rightarrow nH_2SO_4=0.1mol\)
\(\rightarrow VdungdichH_2SO_4=\dfrac{0,1}{1}=0,1l\)
\(n_{H_2SO_4}=\dfrac{1}{2}n_{H_+}=\dfrac{1}{2}n_{OH^-}=\dfrac{0,2}{2}=0,1\left(mol\right)\)
\(\Rightarrow V=0,1\left(l\right)\)