mdd(H2SO4) = D.V = 1,14.100 = 114 gam ---> nH2SO4 = 20.114/100/98 = 0,233 mol.
nBaCl2 = 100.5,2/100/208 = 0,025 mol.
BaCl2 + H2SO4 ---> BaSO4 + 2HCl
---> nH2SO4 dư = 0,233 - 0,025 = 0,208 mol
mdd sau = 114 + 100 - 233.0,025 = 208,175 g ---> C%H2SO4 = 0,208.98.100/208,175 = 9,97%