Question

Triển khai biểu thức theo hằng đẳng thức

(\(\sqrt{x}\)-6) (6 + \(\sqrt{x}\))

(2\(\sqrt{x}\)+1) (2\(\sqrt{x}\)-1)

Answer 1

\(a,\left(\sqrt{x}-6\right)\left(\sqrt{x}+6\right)\)

\(\sqrt{x}^2-6^2\)

\(x-36\)

\(b,\left(2\sqrt{x}+1\right)\left(2\sqrt{x}-1\right)\)

\(\left(2\sqrt{x}\right)^2-1\)

\(4x-1\)

Answer 2

\(\left(\sqrt{x}-6\right)\left(6+\sqrt{x}\right)\)

\(=\left(\sqrt{x}-6\right)\left(\sqrt{x}+6\right)\)

\(=\left(\sqrt{x}\right)^2-6^2\)

\(=x-36\)

b.\(\left(2\sqrt{x}+1\right)\left(2\sqrt{x}-1\right)\)

\(=\left(2\sqrt{x}\right)^2-1^2\)

\(=4x-1\)

Answer 3

Trả lời:

a, \(\left(\sqrt{x}-6\right)\left(6+\sqrt{x}\right)=\left(\sqrt{x}\right)^2-6^2=x-36\)

b, \(\left(2\sqrt{x}+1\right)\left(2\sqrt{x}-1\right)=\left(2\sqrt{x}\right)^2-1^2=4x-1\)