Ta có: \(\left\{{}\begin{matrix}Q_{thu}=mc\Delta t=1,5\cdot4200\cdot80=504000\left(J\right)\\Q_{toa}=UIt=Pt=880\cdot12\cdot60=633600\left(J\right)\end{matrix}\right.\)
\(\Rightarrow H=\dfrac{Q_{thu}}{Q_{toa}}100\%=\dfrac{504000}{633600}100\%\approx79,54\%\)
Áp dụng PTCBN:
\(A=Q_{thu}=Q_{toa}=5\cdot4200\cdot80=1680000\left(J\right)=0,47\)(kWh)
Tiền điện phải trả: \(0,47\cdot1600\cdot30=22560\left(dong\right)\)