\(\dfrac{3}{7}.\left(\dfrac{13}{8}-\dfrac{7}{9}\right)-\dfrac{5}{8}.\left(\dfrac{3}{7}-\dfrac{8}{15}\right)\)
\(=\dfrac{3}{7}.\dfrac{13}{8}-\dfrac{3}{7}.\dfrac{7}{9}-\dfrac{5}{8}.\dfrac{3}{7}-\dfrac{5}{8}.\dfrac{8}{15}\)
\(=\dfrac{3}{7}.\left(\dfrac{13}{8}-\dfrac{5}{8}\right)-\dfrac{3.7}{7.9}-\dfrac{5.8}{8.15}\)
\(=\dfrac{3}{7}.\dfrac{8}{8}-\dfrac{1.1}{1.3}-\dfrac{1.1}{1.3}\)
\(=\dfrac{3}{7}.1-\dfrac{1}{3}-\dfrac{1}{3}\)
\(=\dfrac{3}{7}-\dfrac{1}{3}-\dfrac{1}{3}\)
\(=\dfrac{3}{7}-\left(\dfrac{1}{3}-\dfrac{1}{3}\right)\)
\(=\dfrac{3}{7}-0\)
\(=\dfrac{3}{7}\)
Ta có: \(\dfrac{3}{7}\left(\dfrac{13}{8}-\dfrac{7}{9}\right)-\dfrac{5}{8}\left(\dfrac{3}{7}-\dfrac{8}{15}\right)\)
\(=\dfrac{3}{7}\cdot\dfrac{13}{8}-\dfrac{1}{3}-\dfrac{3}{7}\cdot\dfrac{5}{8}+\dfrac{1}{5}\)
\(=\dfrac{3}{7}\)
