Các câu hỏi tương tự
a)Afrac{1}{1.2}+frac{1}{2.3}+frac{1}{3.4}+...+frac{1}{99.100} 1b)Bfrac{1}{3}+left(frac{1}{3}right)^2+left(frac{1}{3}right)^3+...+left(frac{1}{3}right)^{100} frac{1}{2}c)frac{1}{1.2}+frac{1}{3.4}+frac{1}{5.6}+...+frac{1}{49.50}frac{1}{26}+frac{1}{27}+...+frac{1}{50}d)Afrac{1}{1.2}+frac{1}{3.4}+...+frac{1}{99.100}.CMRfrac{7}{12} A frac{5}{6}AI ĐÚNG MINK left(TICKright)CHO (làm đc trên 2 câu)
Đọc tiếp
a)A=\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}< 1\)
b)B=\(\frac{1}{3}+\left(\frac{1}{3}\right)^2+\left(\frac{1}{3}\right)^3+...+\left(\frac{1}{3}\right)^{100}< \frac{1}{2}\)
c)\(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{49.50}=\frac{1}{26}+\frac{1}{27}+...+\frac{1}{50}\)
d)A=\(\frac{1}{1.2}+\frac{1}{3.4}+...+\frac{1}{99.100}.CMR\frac{7}{12}< A< \frac{5}{6}\)
AI ĐÚNG MINK \(\left(TICK\right)\)CHO (làm đc trên 2 câu)
1. Cho A = 1/(1.2)+1/(3.4)+...+1/(99.100).
Chứng minh 7/12 < A <5/6
2.Chứng minh:
1/(1.2)+1/(3.4)+...+1/(49.50)=1/26+1/27+...+1/50
cho A= 1/1.2+1/3.4+1/5.6+....+1/49.50
B= 1/1+1/2+1/3+1/4+....+1/49+1/50
C=`1/2+1/4+1/6+....+1/48+1/50
Chứng minh A=B-2C
1. Tính và tìm x
a, |3| - căn bậc hai của 11^2-21 - 4^15 : 2^27 + (-1)^2020
b, 1/1.2+1/2.3+1/3.4+.......+1/99.100
c, 1/2+1/2^2+1/2^3+.....+1/2^100
d, 1/1.2+3/2.5+5/5.10+11/10.21+13/21.34+1/34+35
f, ( x - 1/3)^4 .7^13= 7^16
e, |3x-2| - 5 = 11
g, x : 0,25 - x : 0,125 + 5.x= 2109
Cho A =\(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{49.50}\)
B=\(\frac{1}{1}+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{49}+\frac{1}{50}\)
C=\(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{49}+\frac{1}{50}\)
Chứng minh A = B - 2C
gọi a = 1/1.2^2 + 1/2.3^2 + 1/3.4^2 + ... + 1/49.50^2; b = 1/2^2 + 1/3^2 + ... + 1/50^2. cmr a < 1/2 < b
gọi a = 1/1.2^2 + 1/2.3^2 + 1/3.4^2 + ... + 1/49.50^2; b = 1/2^2 + 1/3^2 + ... + 1/50^2. cmr a < 1/2 < b
a) A = 1/1.2+ 1/3.4+ 1/5.6+...+ 1/99.100
CMR: 7/12<A< 5/6
b) CMR: 1/1.2+ 1/3.4+ 1/5.6+...+1/49.50 = 1/26+ 1/27+ 1/28+...+1/50
1, CMR: \(\frac{7}{12}<\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{97.98}+\frac{1}{99.100}<\frac{5}{6}\)
2, CMR: \(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{47.48}+\frac{1}{49.50}=\frac{1}{26}+\frac{1}{27}+\frac{1}{28}+...+\frac{1}{49}+\frac{1}{50}\)