Question

Tính:

a) \(\left(-0,125\right)^3.80^4\)

b) \(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}\)

Answer 1

a/ \(\left(-0,125\right)^3:80^4=-\frac{1}{512}.80^4=-80000\)

b/ \(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}=3\)

Answer 2

a, ( - 0, 125)^3 . 80^ 4 

   \(\left(-\frac{1}{8}\right)^3.80^4=\frac{-1^3}{8^3}\cdot8^4\cdot10^4\)  = \(-8\cdot10^4=-8.1000=-8000\)

b,\(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}=\frac{3^{4.11}.3^{17}}{3^{3.10}.3^{2.15}}=\frac{3^{44}.3^{17}}{3^{30}.3^{30}}=\frac{3^{44+17}}{3^{30+30}}=\frac{3^{61}}{3^{60}}=3\)