Question

Tính
a, \(A=\dfrac{3^{10}.11+3^{10}.5}{3^9.2^4}\)                                    b, \(B=\dfrac{2^{10}.13+2^{10}.65}{2^8.104}\)

c, \(C=\dfrac{4^9.36+64^4}{16^4.100}\)                                      d, \(D=\dfrac{72^3.54^2}{108^4}\)

 

Answer 1

a) \(\dfrac{3^{10}.11+3^{10}.5}{3^9.2^4}=\dfrac{3^{10}\left(11+5\right)}{3^9.16}=\dfrac{3.16}{16}=3\)

b) \(\dfrac{2^{10}.13+2^{10}.65}{2^8.104}=\dfrac{2^{10}\left(13+65\right)}{2^8.26.4}=\dfrac{2^2.26.3}{26.4}=2\)

c) \(\dfrac{4^9.36+64^4}{16^4.100}=\dfrac{4^9.36+4^{12}}{4^8.100}=\dfrac{4^9.\left(36+4^3\right)}{4^8.100}=\dfrac{4.100}{100}=4\)

d) \(\dfrac{72^3.54^2}{108^4}=\dfrac{8^3.3^3.3^3.27^2.2^2}{\left(3^3\right)^4.4^4}=\dfrac{2^9.3^6.3^6.2^2}{3^{12}.2^8}=2^3=8\)