Question

Tính:

1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64

Answer 1

😀

Answer 2

Đặt A = 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64

   2 x A = 1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32

Lấy 2 x A trừ A theo vế ta có :

2 x A = (1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32) - (1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64)

     A  = 1 - 1/64

     A  = 63/64

Vậy A = 63/64

Answer 3

1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64

= 32/64 + 16/64 + 8/64 + 4/64 +2/64 + 1/64

= \(\frac{32+16+8+4+2+1}{64}\)

= \(\frac{63}{64}\)

Answer 4

\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+\frac{1}{16}-\frac{1}{32}+\frac{1}{32}-\frac{1}{64}\)

\(=1-\frac{1}{64}\)

\(=\frac{64}{64}-\frac{1}{54}=\frac{63}{64}\)

_Hắc phong_

Answer 5

1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64

= 1 - 1/2 + 1/2 - 1/4 + 1/4 - 1/16 + 1/16 - 1/32 + 1/32 - 1/64

= 1 - 1/64

= 63/64

Answer 6

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{16}+\frac{1}{16}=1-\frac{1}{64}=\frac{63}{64}\)

~Study well~ :)