Question

tinh

1-1/(x+20)=1005/2011

(luu y:/ la phan)

Answer 1

\(1-\frac{1}{x+20}=\frac{1005}{2011}\)

\(\frac{1}{x+20}=1-\frac{1005}{2011}\)

\(\frac{1}{x+20}=\frac{1006}{2011}\)

=>1006.(x+20)=2011.1

=>1006x+20120=2011

1006x=2011-20120=-18109

x=\(\frac{-18109}{1006}\)

Answer 2

\(1-\frac{1}{\left(x+20\right)}=\frac{1005}{2011}\)

\(\Rightarrow\frac{1}{\left(x+20\right)}=1-\frac{1005}{2011}=\frac{1006}{2011}\)

\(\Rightarrow1:\left(x+20\right)=\frac{1006}{2011}\)

\(\Rightarrow x+20=\frac{2011}{1006}\)

\(\Rightarrow x=\frac{2011}{1006}-20=\frac{-18109}{1006}\)

Answer 3

\(1-\frac{1}{\left(x+20\right)}=\frac{1005}{2011}\)

\(1\div x+20=1-\frac{1005}{2011}\)

\(1\div x+20=\frac{1006}{2011}\)

\(1006\times\left(x+20\right)=2011\)

\(1006x\times20120=2011\)

\(1006x=2011-20120\)

\(1006x=-18109\)

=> Mẫu số = 1006 , Tử số = 18109

\(\Rightarrow x=-\frac{18109}{1006}\)