S=99.100.101/3=333300
Ta có công thức:
1.2+2.3+3.4+...+n(n+1)=n(n+1)(n+2)/3
http://olm.vn/hoi-dap/question/1738.html
S = 1.2 + 2.3 + 3.4 +.... + 99.100
S=(99.100.101-0.1.1):3=333300
S = 1.2 + 2.3 + 3.4 +.... + 99.100
3S=1.2.3+2.3.3+3.4.3+...+99.100.3
3S=1.2.(3-0)+2.3.(4-1)+3.4.(5-2)+...+99.100.(101-98)
3S=1.2.3-0.1.2+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101-98.99.100
3S=(1.2.3-1.2.3)+(2.3.4-2.3.4)+...+(98.99.100-98.99.100)+(99.100.101-0.1.2)
3S=99.100.101-0.1.2
3S=99.100.101
S=(99.100.101):3
S=999900:3
S=333300