Ô tô đi với vận tốc 50km/giờ vì :
100 : 2 = 50
đs : 50
Ta có: C = 1.2 + 2.3 + 3.4 + ..... + 98.99
=> 3C = 3.(1.2 + 2.3 + 3.4 + ..... + 98.99)
=> 3C = 1.2.(3 - 0) + 2.3.(4 - 1) + .... + 98.99.(100 - 97)
=> 3C = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ..... + 98.99.100
=> 3C = 98.99.100
=> C = $C=\frac{98.99.100}{3}=485100$
Trả lời hộ mình câu h= 1.1+2.2+ 3.3+4.4+...+98.98
nhanh lên ai giải câu H đi để mình xem
H=1.1+2.2+3.3+4.4+...+97.97+98.98
H=1.(2-1)+2.(3-1)+3.(4-1)+4.(5-1)+...+97.(98-1)+98.(99-1)
H=1.2-1 + 2.3-2 + 3.4-3 + 4.5-4 + ... + 97.98-97 + 98.99-98
H=1.2 + 2.3 + 3.4 + 4.5 + ... + 97.98 + 98.99 -1 -2 -3 -4 -... -97 - 98
H=(1.2+2.3+3.4+4.5+...+97.98+98.99) - (1+2+3+4+...+97+98)
H=1/3.3.(1.2+2.3+3.4+4.5+...+97.98+98.99) - [(98+1).(98-1+1)] / 2
H=1/3.(1.2.3+2.3.3+3.4.3+4.5.3+...+97.98.3+98.99.3) - [99.98]/2
H=1/3.(1.2.3 + 2.3.(4-1) + 3.4.(5-2) + 4.5.(6-3) +... + 97.98.(99-96) + 98.99.(100-97) - [99.49]
H=1/3.(1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-3.4.5+...+97.98.99+96.97.98+98.99.100-97.98.99) - 4851
H=1/3(98.99.100) - 4851
H=(98.33.100)-4851
H=323400-4851
H==318549