\(=\dfrac{-3}{7}\left(\dfrac{4}{19}+\dfrac{10}{19}\right)+\dfrac{4}{7}\cdot\dfrac{-14}{19}=\dfrac{14}{19}\left(-\dfrac{3}{7}-\dfrac{4}{7}\right)=-\dfrac{14}{19}\)
\(\dfrac{-3}{7}.(\dfrac{4}{19}+\dfrac{10}{19})+\dfrac{4}{7}.\dfrac{-14}{19}\)
\(\dfrac{1}{7}\)