Question

Tính thể tích khí ( đkc) của những chất sau:
1) 19,2 g O₂
2) 5,68 g Cl₂
3) 7,04 g CO₂

Answer 1

\(1,n_{O_2}=\dfrac{19,2}{32}=0,6\left(mol\right)\\ \Rightarrow V_{O_2\left(đkc\right)}=0,6\cdot24,79=14,874\left(l\right)\\ 2,n_{Cl_2}=\dfrac{5,68}{71}=0,08\left(mol\right)\\ \Rightarrow V_{Cl_2\left(đkc\right)}=0,08\cdot24,79=1,9832\left(l\right)\\ 3,n_{CO_2}=\dfrac{7,04}{44}=0,16\left(mol\right)\\ \Rightarrow V_{CO_2\left(đkc\right)}=0,16\cdot24,79=3,9664\left(l\right)\)

Answer 2

1,  nO2=19,2/ 32=0,6 mol

–>V=n. 22,4=0,6. 22,4=13,44 L

2,  nCl2=5,68/ 71=0,08 mol

V Cl2=n. 22,4=0,08. 22,4=1,792 L

3,  nC02=7,04/ 44=0,16 mol

V=0,16. 22,4=3,584 L