\(0,4\left(3\right)=\frac{43-4}{90}=\frac{39}{90}=\frac{13}{30}\)đó Michiel Girl Mít ướt
Đó là công thức đưa 1 số thập phân vô hạn tuần hoàn sang phân số đó Michiel Girl Mít ướt
\(0,4\left(3\right)=\frac{43-4}{90}=\frac{39}{90}=\frac{13}{30}\)đó Michiel Girl Mít ướt
Đó là công thức đưa 1 số thập phân vô hạn tuần hoàn sang phân số đó Michiel Girl Mít ướt
Tính hợp lý nếu có thể:
a) A = 0,4(3)+0,6(2).\(2\frac{1}{2}-\frac{\frac{1}{2}+\frac{1}{3}}{0,5\left(8\right)}:50\frac{50}{53}\)
b) B = [0,(5).0,(2)]:\(\left(3\frac{1}{3}:\frac{33}{25}\right)-\left(\frac{2}{5}.1\frac{1}{3}\right):\frac{4}{3}\)
Giá trị của biểu thức A = \(0,4\left(3\right)+0,6\left(2\right)\cdot2\frac{1}{2}-\frac{\frac{1}{2}+\frac{1}{3}}{0,5\left(8\right)}:\frac{50}{53}\) là:......
Các bạn trình bày bài giải đầy đủ cho mk nhé!
Bạn nào giải đúng mk sẽ tick lun
Tính :
A = 0,4(3) + 0,6(2) x 2 \(\frac{1}{2}\)- \(\frac{\frac{1}{2}+\frac{1}{3}}{0,5\left(8\right)}\) : \(\frac{50}{53}\)
\(0.4\left(3\right)+0.6\left(2\right)\cdot2\frac{1}{2}\cdot\left[\left(\frac{1}{2+\frac{1}{3}}\right):0.5\left(8\right)\right]:\frac{50}{53}\)
Tính:
a) \(3^{-2}.\left(\frac{2}{3}\right)^{-4}.\left(-1\frac{1}{2}\right)^{-3}\)
b) \(0,02^{-3}.10^{-4}.\left(\frac{4}{5}\right)^{-2}.\left(0,4\right)^4\)
c) \(\frac{2^{-2}-\left(\frac{3}{4}\right)^{-4}.\left(-\frac{1}{2}\right)^2}{10^{-1}+\left(-\frac{1}{8}\right)^0}\)
tìm x,y biết:
a)\(\left(2x-5\right)^{2000}+\left(3y+4\right)^{2002}\le0\)
b)\(x=6:\frac{1}{3}-0,8:\frac{1,5}{\frac{3}{2}.0,4.\frac{50}{1:\frac{1}{2}}}+\frac{1}{4}+\frac{1+\frac{1}{2}.\frac{1}{0,25}}{6-\frac{46}{1+2,2.10}}\)
c)\(y=77^{-1}.7^4.11^2.\left(1.11\right)^4.\left(7^2\right)^{-8}.\left(7^{-8}\right)^{-3}.\frac{1}{\left(-11\right)^{-3}}\)
\(\left(\frac{-5}{12}+\frac{7}{4}-\frac{3}{8}\right)-\left[4\frac{1}{2}-7\frac{1}{3}\right]-\left(\frac{1}{4}-\frac{5}{2}\right)\)
\(\left[2\frac{1}{4}-5\frac{3}{2}\right]-\left(\frac{3}{10}-1\right)-5\frac{1}{2}+\left(\frac{1}{3}-\frac{5}{6}\right)\)
\(\frac{4}{7}-\left(3\frac{2}{5}-1\frac{1}{2}\right)-\frac{5}{21}+\left[3\frac{1}{2}-4\frac{2}{3}\right]\)
\(\frac{1}{8}-1\frac{3}{4}+\left(\frac{7}{8}-3\frac{7}{2}+\frac{3}{4}\right)-\left[\frac{7}{4}-\frac{5}{8}\right]\)
\(\left(\frac{3}{5}-2\frac{1}{10}+\frac{11}{20}\right)-\left[\frac{-3}{4}+1\frac{7}{2}\right]\)
\(\left[-2\frac{1}{5}-2\frac{2}{3}\right]-\left(\frac{1}{15}-5\frac{1}{2}\right)+\left[\frac{-1}{6}+\frac{1}{3}\right]\)
\(1\frac{1}{8}-\left(\frac{1}{15}-\frac{1}{2}+\frac{-1}{6}\right)+\left[\frac{5}{4}+\frac{3}{2}\right]\)
\(\frac{5}{6}-\left(1\frac{1}{3}-1\frac{1}{2}\right)+\left[\frac{5}{12}-\frac{3}{4}-\frac{1}{6}\right]\)
\(1\frac{1}{4}-\left(\frac{7}{12}-\frac{2}{3}-1\frac{3}{8}\right)+\left[\frac{5}{24}-2\frac{1}{2}\right]-\frac{1}{6}-\left[\frac{-3}{4}\right]\)
\(-2\frac{1}{5}+2\frac{3}{10}-\left(\frac{6}{20}-\left[\frac{2}{8}-1\frac{1}{2}\right]\right)+\left[\frac{7}{20}-1\frac{1}{4}\right]\)
\(-\left[1\frac{2}{3}-3\frac{1}{2}+\frac{1}{4}\right]+\left(\frac{2}{6}-\frac{5}{12}\right)-\left(\frac{1}{3}-\left[\frac{1}{4}-\frac{1}{3}\right]\right)\)
\(-\frac{4}{5}-\left(1\frac{1}{10}-\frac{7}{10}\right)+\left[\frac{3}{4}-1\frac{1}{5}\right]+1\frac{1}{2}\)
\(\frac{3}{21}-\frac{5}{14}+\left[1\frac{1}{3}-5\frac{1}{2}+\frac{5}{14}\right]-\left(\frac{1}{6}-\frac{3}{7}+\frac{1}{3}\right)\)
\(-1\frac{2}{5}+\left[1\frac{3}{10}-\frac{7}{20}-1\frac{1}{4}\right]-\left(\frac{1}{5}-\left[\frac{3}{4}-1\frac{1}{2}\right]\right)\)
\(2\frac{1}{3}-\left(\frac{1}{2}-2\frac{1}{6}+\frac{3}{4}\right)+\left[\frac{5}{12}-1\frac{1}{3}\right]-\frac{7}{8}+3\frac{1}{2}\)
\(2\frac{1}{4}-1\frac{3}{5}-\left(\frac{9}{20}-\frac{7}{10}\right)+\left[1\frac{3}{5}-2\frac{1}{2}\right]+\frac{3}{4}\)
\(\left[\frac{8}{3}-5\frac{1}{4}+\frac{1}{6}\right]-\frac{7}{4}+\frac{-5}{12}-\left(1-1\frac{1}{2}+\frac{1}{3}\right)\)
\(\left(\frac{1}{4}-\left[1\frac{1}{4}-\frac{7}{10}\right]+\frac{1}{2}\right)-2\frac{1}{5}-1\frac{3}{10}+\left[1-\frac{1}{2}\right]\)
TRÌNH BÀY GIÚP MÌNH NHA
a)\(\left(\frac{1}{13}\right)^{13}:\left(\frac{1}{3}\right)^{x-2}=\frac{1}{81}\)
b)\(\left(0,4\right)^{x-1}:\left(\frac{2}{5}\right)^2=\frac{8}{125}\)
Bài 1 hãy tính
1 . A = \(\frac{9^5.5^7}{45^7}\)
2 .B = \(\left(\frac{2^2.2^3}{4^2.16}\right)^{15}\)\(:\left(\frac{2^6}{16^2}\right)^{10}\)
3 . A= \(\frac{-5.7^5+7^4}{7^6.10-2.7^5}\)
4 . B = \(\frac{10^3+5.10^2.5^3}{-13}\)
5 . A = \(\frac{\left(-0,03\right)^7.2^8}{\left(0,6\right)^7}\)
6 . B= \(\frac{3^7.16^3}{12^5.27^2}\)
7 . A = \(\frac{2^3.\left(0,5\right)^3.3^7}{2.\left(,5\right)^4.3^8}\)
8 . B = \(\left(\frac{-1}{3}\right)^3\)\(.\left(\frac{-1}{3}\right)^2\)\(.\left(\frac{-1}{3}\right)\)
Giúp mik nhé . mik cần ngay