\(\frac{5.\left(2^2\right)^{15}-\left(3^2\right)^9.2^2.3^{20}.\left(2^3\right)^9}{5.2^9.\left(2.3\right)^{19}-7.2^{29}.\left(3^3\right)^6}\)=\(\frac{5.2^{30}-3^{18}.2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)=\(\frac{5.2^{30}-2^{29}.3^{38}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)=\(\frac{2^{29}.\left(5.2-3^{38}\right)}{2^{28}.3^{18}.\left(5.3-7.2\right)}\)=
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