\(P+\frac{1}{512}=\frac{3}{2}+\frac{3}{8}+\frac{3}{32}+\frac{3}{128}+\frac{4}{512}=\frac{3}{2}+\frac{3}{8}+\frac{3}{32}+\frac{4}{128}=\)
\(=\frac{3}{2}+\frac{3}{8}+\frac{4}{32}=\frac{3}{2}+\frac{4}{8}=\frac{4}{2}=2\)
\(\Rightarrow P=2-\frac{1}{512}=\frac{1023}{512}\)
\(P=\frac{3}{2}+\frac{3}{8}+...+\frac{3}{512}\)
\(=3.\left(\frac{1}{2}+\frac{1}{2^3}+\frac{1}{2^5}+\frac{1}{2^7}+\frac{1}{2^9}\right)\)
\(4P=3\left(\frac{1}{2^3}+\frac{1}{2^5}+...+\frac{1}{2^{11}}\right)\)
\(4P-P=3\left(\frac{1}{2}-\frac{1}{2^{11}}\right)\)
\(3P=3\left(\frac{1}{2}-\frac{1}{2^{11}}\right)\)
\(P=\frac{1}{2}-\frac{1}{2^{11}}=\frac{2^{10}-1}{2^{11}}\)
Đinh Thùy LinhTính nhanh mà bạn cách này mk nhanh hơn nhiều :D
ô Dung nhanh quá cách mk giống cah DUng đấy :D
Tui nhầm phải nhân với \(\frac{1}{4}\)
Ông Thắng nếu làm thế kia thì sai r tui làm lại đây
\(P=3\left(\frac{1}{2}+\frac{1}{2^3}+...+\frac{1}{2^9}\right)\)
\(\frac{1}{4}P=3\left(\frac{1}{2^3}+\frac{1}{2^5}+\frac{...1}{2^{11}}\right)\)
\(P-\frac{1}{4}P=3\left(\frac{1}{2}-\frac{1}{2^{11}}\right)\)
\(\frac{3}{4}P=3\left(\frac{1}{2}-\frac{1}{2^{11}}\right)\)
\(P=\left(\frac{1}{2}-\frac{1}{2^{11}}\right).4\)
\(=\frac{2^{10}-1}{2^9}\)