Question

tính nhanh :

\(\frac{1}{1\cdot4}\)+\(\frac{1}{4\cdot7}\)+\(\frac{1}{7\cdot10}\)+....+\(\frac{1}{22\cdot25}\)

dấu chấm là dấu nhân nha

Answer 1

Gọi \(A=\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{22.25}\)

\(\Leftrightarrow\)\(3A=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{22.25}\)

\(\Leftrightarrow\)\(3A=\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{22}-\frac{1}{25}\)

\(\Leftrightarrow\)\(3A=1-\frac{1}{25}\)

\(\Leftrightarrow\)\(3A=\frac{24}{25}\)

\(\Leftrightarrow\)\(A=\frac{24}{25}:3\)

\(\Leftrightarrow\)\(A=\frac{24}{25}.\frac{1}{3}\)

\(\Leftrightarrow\)\(A=\frac{8}{25}\)

Vậy \(A=\frac{8}{25}\)

Answer 2

Đặt \(C=\frac{1}{1.4}+\frac{1}{4.7}+...+\frac{1}{22.25}\)

\(\Rightarrow3C=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+....+\frac{3}{22.25}\)

\(\Rightarrow3C=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{22}-\frac{1}{25}\)

\(\Rightarrow3C=1-\frac{1}{25}=\frac{24}{25}\)

\(\Rightarrow C=\frac{24}{25}:3=\frac{8}{25}\)

Vậy \(\frac{1}{1.4}+\frac{1}{4.7}+...+\frac{1}{22.25}=\frac{8}{24}\)