Question

Tính nhanh : 

             A = \(\frac{6}{4}+\frac{6}{28}+\frac{6}{130}+\frac{6}{70}+\frac{6}{208}\)

Answer 1

A=\(\frac{6}{4}+\frac{6}{28}+\frac{6}{70}+\frac{6}{130}+\frac{6}{208}\)

A=\(\frac{6}{1\cdot4}+\frac{6}{4\cdot7}+\frac{6}{7\cdot10}+\frac{6}{10\cdot13}+\frac{6}{13\cdot16}\)

A:2=\(\frac{3}{1\cdot4}+\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+\frac{3}{10\cdot13}+\frac{3}{13\cdot16}\)

A:2=\(\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+\frac{1}{13}-\)\(\frac{1}{16}\)

A:2=\(1-\frac{1}{16}\)

A:2=\(\frac{15}{16}\)

A=\(\frac{15}{8}\)

vậy ...

Answer 2

Kết quả là

A = 15/8

   Đs...

Answer 3

\(A=\frac{6}{4}+\frac{6}{28}+\frac{6}{70}+\frac{6}{130}+\frac{1}{208}\)

\(\Rightarrow A=\frac{6}{1\cdot4}+\frac{6}{4\cdot7}+\frac{6}{7\cdot10}+\frac{6}{10\cdot13}+\frac{6}{13\cdot16}\)

\(\Rightarrow\)\(\frac{3}{6}A=\frac{3}{6}\cdot\left(\frac{6}{1\cdot4}+\frac{6}{4\cdot7}+\frac{6}{7\cdot10}+\frac{6}{10\cdot13}+\frac{1}{13\cdot16}\right)\)

\(\Rightarrow\)\(\frac{3}{6}A=\frac{3}{1\cdot4}+\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+\frac{3}{10\cdot13}+\frac{3}{13\cdot16}\)

\(\Rightarrow\)\(\frac{3}{6}A=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+\frac{1}{13}-\frac{1}{16}\)

\(\Rightarrow\)\(\frac{3}{6}A=1-\frac{1}{16}\)

\(\Rightarrow\)\(\frac{3}{6}A=\frac{15}{16}\)

\(\Rightarrow A=\frac{15}{16}:\frac{3}{6}\Rightarrow A=\frac{15}{8}\)