Lời giải:
$\frac{6}{4}\times \frac{19}{10}-\frac{3}{4}\times \frac{7}{10}+\frac{3}{4}:\frac{10}{69}$
$=\frac{6}{4}\times \frac{19}{10}-\frac{3}{4}\times \frac{7}{10}+\frac{3}{4}\times \frac{69}{10}$
$=\frac{6}{4}\times \frac{19}{10}+\frac{3}{4}\times (\frac{69}{10}-\frac{7}{10})$
$=\frac{3}{2}\times \frac{19}{10}+\frac{3}{4}\times \frac{62}{10}$
$=\frac{3}{2}\times \frac{19}{10}+\frac{3}{2}\times \frac{31}{10}$
$=\frac{3}{2}\times (\frac{19}{10}+\frac{31}{10})$
$=\frac{3}{2}\times \frac{50}{10}=\frac{3}{2}\times 5=\frac{15}{2}$