)\(\frac{12.\left(1-\frac{1}{7}-\frac{1}{13}-\frac{1}{17}\right)}{4.\left(1-\frac{1}{7}-\frac{1}{13}-\frac{1}{17}\right)}:\frac{5.\left(1+\frac{1}{7}+\frac{1}{13}+\frac{1}{17}\right)}{6.\left(1+\frac{1}{7}+\frac{1}{13}+\frac{1}{17}\right)}\)
\(=\frac{12}{4}+\frac{5}{6}=\frac{18}{6}+\frac{5}{6}=\frac{23}{6}\)