Question

tÍnh giá trị của biểu thức sau:

Q=1+1/2 (1+2)+1/3 (1+2+3)+.....+1/16(1+2+3+....+16)

Answer 1

Q = 1+ \(\dfrac{1}{2}\) .(1+2)+ \(\dfrac{1}{3}\) . (1 + 2 + 3) +...+ \(\dfrac{1}{16}\) (1+2+3+...+16)

Q = = 1 + \(\dfrac{1}{2}\) .\(\dfrac{2.3}{2}\) + \(\dfrac{1}{3}\) .\(\dfrac{3.4}{2}\) +...+ \(\dfrac{1}{16}\). \(\dfrac{16.17}{2}\)

Q = \(\dfrac{2}{2}+\dfrac{3}{2}+\dfrac{4}{2}+...+\dfrac{17}{2}\)

Q = \(\dfrac{1}{2}\left(3+4+...+17\right)\)

Q = 76