Question

Tính giá trị biểu thức:

\(A=\left(\frac34-\frac56\right):\left\lbrack\frac78-\left(\frac12+\frac{3}{16}\right)_{}\right\rbrack\)

Answer 1

`A = (3/4 - 5/6) : [7/8 - (1/2 + 3/16)]`

`=> A = (9/12 - 10/12) : [7/8 - (8/16 + 3/16)]`

`=> A = (-1/12) : (7/8 -11/16)`

`=> A = (-1/12) :(14/17 - 11/16)`

`=> A = (-1/12) : 3/16`

`=> A = (-1)/12 xx 16/3`

`=> A = ((-1)*16)/(12*3) = -16/36 = -4/9`

Vậy `A = -4/9`

Answer 2

help

Answer 3

\(A=\left(\frac34-\frac56\right):[\frac78-\left(\frac12+\frac{13}{6}\right)]\)

\(A=\left(\frac{9}{12}-\frac{10}{12}\right):[\frac78-\left(\frac{8}{16}+\frac{3}{16}\right)]\)

\(A=-\frac{1}{12}:[\frac{14}{16}-\frac{11}{16}]\)

\(A=-\frac{1}{12}:\frac{3}{16}\)

\(A=-\frac{8}{18}\)

Answer 4

=(18/24 - 20/24) : [ 7/8 -(8/16 + 3/16)]

=-2/24:[7/8-11/16]

= -1/12:[14/16-11/16]

=-1/12:3/16

=-16/36

Answer 5

\(A=-\frac{8}{18}=-\frac49\)

Answer 6

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Answer 7

-16/36=-4/9

Answer 8

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Answer 9

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Answer 10

A=(3/4−5/6):[7/8−(1/2+3/16)]

\(= > A = \left(\right. 9 / 12 - 10 / 12 \left.\right) : \left[\right. 7 / 8 - \left(\right. 8 / 16 + 3 / 16 \left.\right) \left]\right.\)

\(= > A = \left(\right. - 1 / 12 \left.\right) : \left(\right. 7 / 8 - 11 / 16 \left.\right)\)

\(= > A = \left(\right. - 1 / 12 \left.\right) : \left(\right. 14 / 17 - 11 / 16 \left.\right)\)

\(= > A = \left(\right. - 1 / 12 \left.\right) : 3 / 16\)

\(= > A = \left(\right. - 1 \left.\right) / 12 x x 16 / 3\)

\(= > A = \left(\right. \left(\right. - 1 \left.\right) * 16 \left.\right) / \left(\right. 12 * 3 \left.\right) = - 16 / 36 = - 4 / 9\)

Vậy \(A = - 4 / 9\)