Question

Tính giá trị biểu thức:

A= (b+a)+(c-d)-(c+a)-(b-d)

B=(a-d)-(d+a)-(c-d)+(c+b)

Answer 1

Tham khảo

\(A=\left(b+a\right)+\left(c-d\right)-\left(c+a\right)-\left(b-d\right)\)

\(A=b+a+c-d-c-a-b+d\)

\(A=\left(b-b\right)+\left(a-a\right)+\left(c-c\right)+\left(-d+d\right)\)

\(A=0\)

 

\(B=\left(a-d\right)-\left(d+a\right)-\left(c-d\right)+\left(c+b\right)\)

\(B=a-d-d-a-c+d+c+b\)

\(B=\left(a-a\right)+\left(d-d+d\right)+\left(-c+c\right)+b\)

\(B=d+b\)

Answer 2

a) Ta có: \(A=\left(b+a\right)+\left(c-d\right)-\left(c+a\right)-\left(b-d\right)\)

\(=a+b+c-d-c-a-b+d\)

=0

b) Ta có: \(B=\left(a-d\right)-\left(a+d\right)-\left(c-d\right)+\left(c+b\right)\)

\(=a-d-a-d-c+d+c+b\)

=b-d