\(\frac{2}{3}+\frac{3}{4}:\frac{6}{7}+\frac{1}{8}.\frac{4}{3}\)
=\(\frac{2}{3}+\frac{3}{4}.\frac{7}{6}+\frac{1}{8}.\frac{4}{3}\)
=\(\frac{2}{3}+\frac{7}{8}+\frac{1}{6}\)
=\(\left(\frac{2}{3}+\frac{1}{6}\right)+\frac{7}{8}\)
=\(\frac{5}{6}+\frac{7}{8}\)
=\(\frac{41}{24}\)