Mình nghĩ kết quả là: 2013/2014
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Đặt \(B=\frac{2013}{1}+\frac{2012}{2}+\frac{2011}{3}+....+\frac{1}{2013}\)
\(=\left(\frac{2012}{2}+1\right)+\left(\frac{2011}{3}+1\right)+\left(\frac{2010}{4}+1\right)+.....+\left(\frac{1}{2013}+1\right)+1\)
\(=\frac{2014}{2}+\frac{2014}{3}+\frac{2014}{4}+\frac{2014}{5}+...+\frac{2014}{2013}+\frac{2014}{2014}\)
\(=2014\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{2014}\right)\)
Đặt \(B=\frac{2013}{2}+\frac{2013}{3}+\frac{2013}{4}+....+\frac{2013}{2014}\)
\(=2013\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{2014}\right)\)
\(\Rightarrow\) Biểu thức tương đương với:
\(\frac{2013\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+.....+\frac{1}{2014}\right)}{2014\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{2014}\right)}=\frac{2013}{2014}\)
\(\frac{\frac{2013}{2}+\frac{2013}{3}+...+\frac{2013}{2014}}{2013+\frac{2012}{2}+\frac{2011}{3}+...+\frac{1}{2013}}=\frac{2013\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2014}\right)}{1+\frac{2012}{2}+1+\frac{2011}{3}+...+1+\frac{1}{2013}+1}\)
\(=\frac{2013\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2014}\right)}{\frac{2014}{2}+\frac{2014}{3}+...+\frac{2014}{2013}+\frac{2014}{2014}}\)
\(=\frac{2013\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2014}\right)}{2014\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2014}\right)}\)
\(=\frac{2013}{2014}\)