Question

Tính các tổng sau A= 1+2+2²+2³+2⁴+...+2¹⁰

Answer 1

mik tính mt ra 2047 k bjt có đúng k nữa

Answer 2

A= 1+2² + 2² + 2³ +.....+ 2¹⁰

A= (2^11 -1)/(2-1)

A= 2047

Answer 3

\(A=1+2+2^2+...+2^{10}\)

\(2A=2\times\left(1+2+2^2+...+2^{10}\right)\)

\(2A=2+2^2+2^3+...+2^{11}\)

\(\Rightarrow A=2A-A=\left(2+2^2+2^3+...+2^{11}\right)-\left(1+2+2^2+...+2^{10}\right)\)

\(A=2^{11-1}\)

\(A=2017\)

Answer 4

A=1+2+2²+2³+2⁴+..+2¹⁰

=>2A=2(1+2+2²+2³+2⁴+..+2¹⁰)

=>2A=2+2²+2³+2⁴+2⁵⁺...+2¹¹

=>2A - A=(2+2²+2³+2⁴+2⁵⁺...+2^{11) -} (1+2+2²+2³+2⁴+..+2¹⁰)

=>A=2¹¹-1

=>A=2047

Answer 5

A = 1 + 22 + 23 + 24 + ... + 210

2A = 2 + 23 + 24 + 25 + ... + 210

2A - A = (2 + 23 + 24 + 25 + ... + 211) - (1 + 22 + 23 + 24 + ... + 210)

A = 2 + 210 - 1 - 4

= 210 - 3

=> 207 

Vậy kết quả : 207 

Answer 6

Ta có: 2A=2+2²+2³+2⁴+....+2¹¹

   =>2A-A=(2+2²+2³+2⁴+....+2¹¹)-(1+2+2²+2³+....+2^10)

   =>A=2¹¹-1

          =2048-1

          =2047

Hok tốt

Answer 7

\(A=1+2+2^2+\cdot\cdot\cdot+2^{10}\)

\(\Rightarrow2A=2+2^2+2^3+\cdot\cdot\cdot+2^{11}\)

\(\Rightarrow2A-A=\left(2+\cdot\cdot\cdot+2^{11}\right)-\left(1+\cdot\cdot\cdot+2^{10}\right)\)

\(\Rightarrow A=2^{11}-1\)

Answer 8

trả lời :

A=2047