*Ta có: A=2D (1)
A+D=180 (2)
Thay (1) vào (2) ta đươc:
A+D=180\(\Rightarrow\)2D+D=180\(\Rightarrow\)3D=180
\(\Rightarrow\)D=\(\frac{180}{3}\)=60\(\Rightarrow\)A=2D=2*60=120
*Ta có: B+C=180 (1)
MÀ B-C=20\(\Rightarrow\)B=20+C (2)
Thay (1) vào (2) \(\Rightarrow\)B+C=180
\(\Rightarrow\)20+C+C=180
\(\Rightarrow\)20+2D=180
\(\Rightarrow\)2D=180-20
\(\Rightarrow\)2D=160
\(\Rightarrow\)D=\(\frac{160}{2}=80\)