\(=\lim\limits_{x\rightarrow1}\dfrac{2x-\dfrac{1}{2}.x^{-\dfrac{1}{2}}}{\dfrac{1}{2}.x^{-\dfrac{1}{2}}}=\dfrac{2-\dfrac{1}{2}}{\dfrac{1}{2}}=3\)
\(=\lim\limits_{x\rightarrow1}\dfrac{2x-\dfrac{1}{2}.x^{-\dfrac{1}{2}}}{\dfrac{1}{2}.x^{-\dfrac{1}{2}}}=\dfrac{2-\dfrac{1}{2}}{\dfrac{1}{2}}=3\)
Tính giới hạn L = \(\lim\limits_{x\rightarrow1}\dfrac{\sqrt{2x-1}.\sqrt[3]{x+7}-2}{x^2-x}\)
Tính giới hạn sau:
\(\lim\limits_{x\rightarrow1}\dfrac{\left(x^2+3x+1\right)\sqrt{1+3x}-10}{x^2-1}\)
Tìm giới hạn:
\(\lim\limits_{x\rightarrow1}\dfrac{\sqrt[4]{x}-1}{x^3+x-2}\)
Bài 1. Tìm các giới hạn sau:
a) \(\lim\limits\dfrac{-2n+1}{n}\)
b) \(\lim\limits_{x\rightarrow1}\dfrac{3-\sqrt{x+8}}{x-1}\)
Tìm giới hạn:
a, \(\lim\limits_{x\rightarrow1}\dfrac{\sqrt[3]{x+7}-\sqrt{5-x^2}}{x-1}\)
b, \(\lim\limits_{x\rightarrow5}\dfrac{x-5}{\sqrt{x}-\sqrt{5}}\)
Kết quả giới hạn \(\lim\limits_{x\rightarrow1}\dfrac{\sqrt{x+3}-2}{x-1}\) bằng:
A. 0
B. \(\dfrac{1}{2}\)
C. \(\dfrac{1}{4}\)
D. \(\dfrac{1}{3}\)
Tìm giới hạn của hàm số sau:
\(\lim\limits_{x\rightarrow1}\dfrac{\sqrt{2x+7}-3}{x-1}\)
Tìm giới hạn:
a, \(\lim\limits_{x\rightarrow1}\dfrac{\sqrt{5-x}-\sqrt[3]{x^2+7}}{x^2-1}\)
b, \(\lim\limits_{x\rightarrow4}\dfrac{x^2-4x}{x^2+x-20}\)
Tính các giới hạn sau:
a) \(\lim\limits_{x\rightarrow0^-}\dfrac{2\left|x\right|+x}{x^2-x}\)
b) \(\lim\limits_{x\rightarrow-\infty}\left(\sqrt{x^2-x}-\sqrt{x^2-1}\right)\)
c) \(\lim\limits_{x\rightarrow-\infty}\dfrac{\sqrt[3]{1+x^4+x^6}}{\sqrt{1+x^3+x^4}}\)