Bài 1: Căn bậc hai
Các câu hỏi tương tự
Cho biểu thức:
\(M=\left(\frac{\sqrt{x}+1}{\sqrt{2x}+1}+\frac{\sqrt{2x}+\sqrt{x}}{\sqrt{2x}-1}-1\right)\)\(:\left(1+\frac{\sqrt{x}+1}{\sqrt{2x}+1}-\frac{\sqrt{2x}+\sqrt{x}}{\sqrt{2x}-1}\right)\)
a/ Rút gọn M
b/ Tính M khi \(x=\frac{1}{2}\left(3+2\sqrt{2}\right)\)
Cho biểu thức: B = \(\left(\frac{8x\sqrt{x}-1}{2x-\sqrt{x}}-\frac{8x\sqrt{x}+1}{2x+\sqrt{x}}\right):\frac{2x+1}{2x-1}\) \(\left(x\ge0;x\ne\pm\frac{1}{2}\right)\)
Rút gọn B
Cho \(x=\frac{1}{2}\sqrt{\frac{\sqrt{2}-1}{\sqrt{2}+1}}\). Tính:
\(M=\left(4x^5+4x^4-x^3+1\right)^{19}+\left(\sqrt{4x^5+4x^4-5x^3+5x+3}\right)^3+\left(\frac{1-\sqrt{2}}{\sqrt{2x^2+2x}}\right)^{2016}\)
Tìm x:
a) left(5x-6right)^2-frac{1}{sqrt{5x-7}}x^2-frac{1}{sqrt{x-1}}
b) 4x^3+x-left(x+1right)sqrt{2x+1}0
c) frac{sqrt{x+1}-2}{sqrt[3]{2x+1}-3}frac{1}{x+2}
d) -2x^3+10x^2-17x+82x^2sqrt[3]{5x-x^2}
e) 9x^2-28x+21sqrt{x-1}
f) 3xleft(2+sqrt{9x^2+3}right)+left(4x+2right)sqrt{1+x+x^2}+10
Mng giúp em với ạ, em cảm ơn
Đọc tiếp
Tìm x:
a) \(\left(5x-6\right)^2-\frac{1}{\sqrt{5x-7}}=x^2-\frac{1}{\sqrt{x-1}}\)
b) \(4x^3+x-\left(x+1\right)\sqrt{2x+1}=0\)
c) \(\frac{\sqrt{x+1}-2}{\sqrt[3]{2x+1}-3}=\frac{1}{x+2}\)
d) \(-2x^3+10x^2-17x+8=2x^2\sqrt[3]{5x-x^2}\)
e) \(9x^2-28x+21=\sqrt{x-1}\)
f) \(3x\left(2+\sqrt{9x^2+3}\right)+\left(4x+2\right)\sqrt{1+x+x^2}+1=0\)
Mng giúp em với ạ, em cảm ơn
Cho biểu thức:
\(M=\left(\frac{\sqrt{x}+1}{\sqrt{2x}+1}+\frac{\sqrt{2x}+\sqrt{x}}{\sqrt{2x}+1}-\frac{\sqrt{2x}+\sqrt{x}}{\sqrt{2x}-1}\right)\)
a/ Rút gọn M
b/ Tính M khi \(x=\frac{1}{2}\left(3+2\sqrt{2}\right)\)
a,\(\left(4.\sqrt{x-1}-7\right).\left(2-\sqrt{x-1}\right)=5-4x\)
b,\(\frac{2}{5}.\left(\sqrt{2x+1}+5\right)=\frac{1}{4}.\left(\sqrt{2x+1}-1\right)\)
mn ơi giúp mik vs :((
Rút gọn \(\left(\frac{1}{\sqrt{x}-\sqrt{x}-1}-\frac{x-3}{\sqrt{x}-1-\sqrt{2}}\right)\left(\frac{2}{\sqrt{2}-\sqrt{x}}-\frac{\sqrt{x}+\sqrt{2}}{\sqrt{2x}-x}\right)\)
Cho biểu thức \(A=\left(\frac{\sqrt{x}-4x}{1-4x}-1\right):\left(\frac{1+2x}{1-4x}-\frac{2\sqrt{x}}{2\sqrt{x}-1}-1\right)\)
a) Rút gọn A
b) Tìm các giá trị của x để \(A>A^2\)
c) Tìm các giá trị của x để \(\left|A\right|>\frac{1}{4}\)
Dleft ( frac{1}{3sqrt{x}-6} +frac{1}{x-2sqrt{x}}right )left ( frac{1}{6} +frac{1}{2sqrt{x}}right ) Dleft ( frac{1}{3left ( sqrt{x}-2 right )} +frac{1}{sqrt{x}left ( sqrt{x}-2 right )}right ).frac{sqrt{x}+3}{6sqrt{x}} Dfrac{sqrt{x}+3}{3sqrt{x}left ( sqrt{x}-2 right )}.frac{sqrt{x}+3}{6sqrt{x}} Dfrac{left ( sqrt{x}+3 right )^{2}}{18xleft ( sqrt{x}-2 right )} Dfrac{x+6sqrt{x}+9}{18xsqrt{x}-36x}
A/ Đúng
B/ Sai
Đọc tiếp
\[D=\left ( \frac{1}{3\sqrt{x}-6} +\frac{1}{x-2\sqrt{x}}\right )\left ( \frac{1}{6} +\frac{1}{2\sqrt{x}}\right )\\ D=\left ( \frac{1}{3\left ( \sqrt{x}-2 \right )} +\frac{1}{\sqrt{x}\left ( \sqrt{x}-2 \right )}\right ).\frac{\sqrt{x}+3}{6\sqrt{x}}\\ D=\frac{\sqrt{x}+3}{3\sqrt{x}\left ( \sqrt{x}-2 \right )}.\frac{\sqrt{x}+3}{6\sqrt{x}}\\ D=\frac{\left ( \sqrt{x}+3 \right )^{2}}{18x\left ( \sqrt{x}-2 \right )}\\ D=\frac{x+6\sqrt{x}+9}{18x\sqrt{x}-36x}\]
A/ Đúng
B/ Sai