Question

Tinh A=\(\frac{\frac{2}{3}+\frac{2}{5}-\frac{2}{9}}{\frac{4}{3}+\frac{4}{5}-\frac{4}{9}}\)
 

Answer 1

A = \(\frac{2.\left(\frac{1}{3}+\frac{1}{5}-\frac{1}{9}\right)}{4.\left(\frac{1}{3}+\frac{1}{5}-\frac{1}{9}\right)}=\frac{2}{4}=\frac{1}{2}\)

Answer 2

Ở mẫu đặt 2 ra ngoài bên trong coôn lại như tử kq là 1/2

l

Answer 3

Ta có:

\(A=\frac{\frac{2}{3}+\frac{2}{5}-\frac{2}{9}}{\frac{4}{3}+\frac{4}{5}-\frac{4}{9}}\)

\(\Rightarrow A=\frac{2.\left(\frac{1}{3}+\frac{1}{5}-\frac{1}{9}\right)}{4.\left(\frac{1}{3}+\frac{1}{5}-\frac{1}{9}\right)}\)

\(\Rightarrow A=\frac{2}{4}=\frac{1}{2}\)

Vậy \(A=\frac{1}{2}\)