\(\Rightarrow A=\frac{2^{20}+3.5.\left(2^2\right)^9.\left(3^2\right)^4}{\left(2.3\right)^9.2^{10}+\left(2^2.3\right)^{10}}=\frac{2^{20}+3.5.2^{18}.3^8}{2^9.3^9.2^{10}+2^{20}.3^{10}}=\frac{2^{20}+3^9.5.2^{18}}{2^{19}.3^9+2^{20}.3^{10}}=\frac{2^{18}\left(2^2+3^9.5\right)}{2^{19}.3^9\left(1+2.3\right)}=\frac{4.19683}{2.19683.7}=\frac{4}{2.7}=\frac{2}{7}\)
0,3571573729
làm tròn tới chữ số thập phân thứ 2 = 0,36
A = \(\frac{2^{19}.2+15.4^9.9^4}{6^9.2^{10}+12^{10}}=\frac{2^{20}+3.5.\left(2^2\right)^9.\left(3^2\right)^4}{\left(2.3\right)^9.2 ^{10}+\left(2^2.3\right)^{10}}=\frac{2^{20}+3.3^8.2^{18}.5}{2^9.2^{10}.3^9+2^{20}.3^{10}}=\frac{2^{18}.\left(2^2+3^9.5\right)}{2^{19}.3^9\left(1+2.3\right)}=\frac{4+3^9.5}{2.3^9.7}\)
Đề cóa sai k?
