Question

Tính A=1/2+1/4+1/8+1/16+...(tổng có 10 số hạng)

Answer 1

Lời giải:

$A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}+\frac{1}{256}+\frac{1}{512}+\frac{1}{1024}$
$2\times A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}+\frac{1}{256}+\frac{1}{512}$

$\Rightarrow 2\times A-A=1-\frac{1}{1024}$

$\Rightarrow A=\frac{1023}{1024}$