Question

Tính 

a, 10\(\dfrac{2}{9}\) + 2\(\dfrac{2}{5}\) - 6\(\dfrac{2}{9}\)

b, 8\(\dfrac{2}{7}\) - ( 3\(\dfrac{4}{9}\) + 4\(\dfrac{2}{7}\)  )

c, 4\(\dfrac{2}{3}\) + 2\(\dfrac{3}{4}\) x 7\(\dfrac{8}{11}\)

d, 5\(\dfrac{1}{8}\) - 1\(\dfrac{3}{4}\) : 2\(\dfrac{1}{5}\)

Answer 1

\(a,\dfrac{92}{9}+\dfrac{12}{5}-\dfrac{56}{9}=\dfrac{460}{45}+\dfrac{108}{45}-\dfrac{280}{45}=\dfrac{288}{45}=\dfrac{32}{5}\)

\(b,\dfrac{68}{7}-\left(\dfrac{41}{9}+\dfrac{30}{7}\right)=\dfrac{68}{7}-\left(\dfrac{287}{63}+\dfrac{270}{63}\right)=\dfrac{68}{7}-\dfrac{557}{63}=\dfrac{612}{63}-\dfrac{557}{63}=\dfrac{55}{63}\)

\(c,\dfrac{14}{3}+\dfrac{11}{4}.\dfrac{85}{11}=\dfrac{14}{3}+\dfrac{85}{4}=\dfrac{56}{12}+\dfrac{255}{12}=\dfrac{311}{12}\)

\(d,\dfrac{41}{8}-\dfrac{7}{4}:\dfrac{11}{5}=\dfrac{41}{8}-\dfrac{7}{4}.\dfrac{5}{11}=\dfrac{41}{8}-\dfrac{35}{44}=\dfrac{451}{88}-\dfrac{70}{88}=\dfrac{381}{88}\)

Answer 2

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