Ta có: \(\left(7-\dfrac{4}{3}+\dfrac{1}{3}\right)-\left(6+\dfrac{5}{4}-\dfrac{4}{3}\right)-\left(5\cdot\dfrac{7}{4}+\dfrac{5}{3}\right)\)
\(=6-\left(\dfrac{72}{12}+\dfrac{15}{12}-\dfrac{16}{12}\right)-\left(\dfrac{35}{4}+\dfrac{5}{3}\right)\)
\(=6-\dfrac{71}{12}-\dfrac{125}{12}\)
\(=\dfrac{-124}{12}=\dfrac{-62}{6}=\dfrac{-31}{3}\)