Question

tính

 (√6+2)(√3-√2)

(√8/3-√24+√50/3)

Answer 1

a/ \(\left(\sqrt{6}+2\right)\left(\sqrt{3}-\sqrt{2}\right)=\sqrt{2}\left(\sqrt{3}+2\right)\left(\sqrt{3.1}-\sqrt{2.1}\right)=\sqrt{2}\left(3-2\right)=\sqrt{2}\)

b/ \(\left(\sqrt{\frac{8}{3}-\sqrt{24}+\sqrt{\frac{50}{3}}}\right)=-\frac{4\sqrt{6}}{3}+\frac{5\sqrt{6}}{3}=\frac{\sqrt{6}}{3}\)

Answer 2

a/ \(=\sqrt{2}\left(\sqrt{3}+\sqrt{2}\right)\left(\sqrt{3}-\sqrt{2}\right)=\sqrt{2}\left(3-2\right)=\sqrt{2}\)

b/ \(=\frac{2\sqrt{2}-2\sqrt{6}+5\sqrt{2}}{3}=\frac{-2\sqrt{6}+7\sqrt{2}}{3}\)