Question

Tính:

3(2^2+1)(2^4+1)(2^8+2)(2^16+1)

Answer 1

Đặt \(A=3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)

\(\Rightarrow\left(2^2-1\right)A=3\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)

\(\Rightarrow3A=3\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)

\(\Rightarrow A=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)

\(\Rightarrow A=\left(2^{16}-1\right)\left(2^{16}+1\right)=2^{32}-1\)

Vậy....................

Chúc bạn học tốt!!!

Answer 2

Nếu không biết cách tính nhanh thì nhân hết ra