1/5+1/25+1/25=1*5/25+1/25+1/25=5/25+1/25+1/25=5+1+1/25=7/25
Đổi: \(\frac{1}{5}=\frac{25}{125}\)
\(\frac{1}{25}=\frac{5}{125}\)
Vậy \(\frac{1}{5}+\frac{1}{25}+\frac{1}{125}=\frac{25}{125}+\frac{5}{125}+\frac{1}{125}\)= \(\frac{31}{125}\)
MC(5; 25; 125)=125
Ta có: \(\frac{1}{5}=\frac{1.25}{5.25}\frac{25}{125}\)và \(\frac{1}{25}=\frac{1.5}{25.5}=\frac{5}{125}\) và giữ nguyên \(\frac{1}{125}\)
=> \(\frac{1}{5}+\frac{1}{25}+\frac{1}{125}\)=\(\frac{25}{125}+\frac{5}{125} +\frac{1}{125}\)= \(\frac{25+5+1}{125}\)=\(\frac{31}{125}\)
Vậy : \(\frac{1}{5}+\frac{1}{25}+\frac{1}{125}\)=\(\frac{31}{125}\)