Question

Tính 

0,1(6) + 1, ( 3 )

1,(3) + 0,1(2) . \(2\frac{8}{11}\)

0,(6) + 1,(6)

3,(6) + 1,(36) x \(2\frac{1}{5}\)

Answer 1

a) 0,16 + 1,3

= \(\frac{4}{25}+\frac{13}{10}\)

= \(\frac{40}{250}+\frac{325}{250}\)

= \(\frac{73}{50}\)

b) 1,3 + 0,12 . \(2\frac{8}{11}\)

= \(\frac{13}{10}+\frac{3}{25}\times\frac{30}{11}\)

= \(\frac{13}{10}+\frac{18}{55}\)

= \(\frac{143}{110}+\frac{36}{110}\)

= \(\frac{179}{110}\) 

c) 0,6 + 1,6

= \(\frac{3}{5}+\frac{8}{5}\)

= \(\frac{11}{5}\)

d) 3,6 + 1,36 \(\times\)\(2\frac{1}{5}\)

= \(\frac{18}{5}+\frac{34}{25}\times\frac{11}{5}\)

= \(\frac{18}{5}+\frac{374}{125}\)

= \(\frac{450}{125}+\frac{374}{125}\)

= \(\frac{824}{125}\)