x^2+2015x-2016=0
<=>(x^2-1)+(2016x-2016)=0
<=>(x-1)(x+1)+2016(x-1)=0
<=>(x-1)(x+2007)=0
<=>x-1=0 hoặc x+2007=0
<=>x=1 hoặc x=-2007
Vậy...
C1ta có:x^2+2015*x-2016=0
denta:20152-(-4(1.2016))=4068289
x1=(-2015+\(\sqrt{4068289}\)):2=1
x2=(-2015-\(\sqrt{4068289}\)):2=-2016
C2:vi-ét:x1+x2=-b/a=-2015
x1*x2=c/a=-2016
=>x=-2016 hoặc 1
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