a) (2x+1)2=25
(2x+1)2= (+-5)2
=> 2x+1 = 5 hoặc 2x + 1 = -5
2x = 4 hoặc 2x = -6
x= 2 hoặc x=-3
b) (x-1)3=-125
(x-1)3= (-5)3
=> x-1 = -5
x= -4
c) 2x+2-2x=96
2x.22 - 2x = 96
2x( 4-1) = 96
2x = 96 : 3
2x= 32
2x = 25
=> x= 5
d) 7x+2+2.7x-1=345
7x-1 . 73 + 2.7x-1=345
7x-1( 73 +2) = 345
7x-1 . 345 = 345
7x-1 =1
=> x-1 = 0
=> x= 1
a) Ta có: \(\left(2x+1\right)^2=25\)
\(\Rightarrow\left(2x+1\right)^2=5^2=\left(-5\right)^2\)
\(\Rightarrow x=2\)hoặc \(x=-3\)
b) \(\left(x-1\right)^3=-125\)
\(\Rightarrow\left(x-1\right)^3=\left(-5\right)^3\)
\(\Rightarrow x=-4\)
c) \(2^{x+2}-2^x=96\)
\(\Rightarrow2^x.2^2-2^x=96\)
\(\Rightarrow2^x\left(2^2-1\right)=96\)
\(\Rightarrow2^x.3=96\)\(\Rightarrow2^x=96\div3=32\)
\(\Rightarrow x=5\)
d)\(7^{x+2}+2.7^{x-1}=345\)
Làm tương tự phần c) bạn nhé
Ta có : (2x + 1)2 = 25
=> (2x + 1)2 = 52 = (-5)2
\(\Rightarrow\orbr{\begin{cases}2x+1=5\\2x+1=-5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x=4\\2x=-6\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=2\\x=-3\end{cases}}\)