Câu hỏi của Trần Phúc Đông

Question

Tìm y :$\frac{9}{10}x100-\left(\frac{5}{2}:\left(y+\frac{206}{100}\right)\right):\frac{1}{2}=89$

Trang Nguyễn · Accepted Answer

$\frac{9}{10}.100-\left(\frac{5}{2}\left(y+\frac{206}{100}\right)\right):\frac{1}{2}=89$$90-\left(\frac{5}{2}\left(y+\frac{103}{50}\right)\right)=89.\frac{1}{2}$$90-\left(\frac{5}{2}\left(y+\frac{103}{50}\right)\right)=\frac{89}{2}$$\frac{5}{2}\left(y+\frac{103}{50}\right)=90-\frac{89}{2}$$\frac{5}{2}\left(y+\frac{103}{50}\right)=\frac{180}{2}-\frac{89}{2}$$\frac{5}{2}\left(y+\frac{103}{50}\right)=\frac{91}{2}$$y+\frac{103}{50}=\frac{91}{2}.\frac{2}{5}$$y+\frac{103}{50}=\frac{91}{5}$$y=\frac{91}{5}-\frac{103}{50}$$y=\frac{910}{50}-\frac{103}{50}$$y=\frac{807}{50}$Câu trả lời: $\frac{9}{10}.100-\left(\frac{5}{2}\left(y+\frac{206}{100}\right)\right):\frac{1}{2}=89$$90-\left(\frac{5}{2}\left(y+\frac{103}{50}\right)\right)=89.\frac{1}{2}$$90-\left(\frac{5}{2}\left(y+\frac{103}{50}\right)\right)=\frac{89}{2}$$\frac{5}{2}\left(y+\frac{103}{50}\right)=90-\frac{89}{2}$$\frac{5}{2}\left(y+\frac{103}{50}\right)=\frac{180}{2}-\frac{89}{2}$$\frac{5}{2}\left(y+\frac{103}{50}\right)=\frac{91}{2}$$y+\frac{103}{50}=\frac{91}{2}.\frac{2}{5}$$y+\frac{103}{50}=\frac{91}{5}$$y=\frac{91}{5}-\frac{103}{50}$$y=\frac{910}{50}-\frac{103}{50}$$y=\frac{807}{50}$

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