Question

Tìm y biết ( \(\frac{5}{7}\)-  y  ) nhân \(\frac{14}{5}\)= \(\frac{7}{10}\)+ \(\frac{1}{2}\)

Toán violymic lớp 5 nhé

Answer 1

\(\left(\frac{5}{7}-y\right)x\frac{14}{5}=\frac{7}{10}+\frac{1}{2}\)

\(\left(\frac{5}{7}-y\right)x\frac{14}{5}=\frac{6}{5}\)

\(\frac{5}{7}-y=\frac{6}{5}:\frac{14}{5}\)

\(\frac{5}{7}-y=\frac{3}{7}\)

Y = \(\frac{5}{7}-\frac{3}{7}\)

Y = \(\frac{2}{7}\)

Answer 2

\(\left(\frac{5}{7}-y\right).\frac{14}{5}=\frac{7}{10}+\frac{1}{2}\)

\(\left(\frac{5}{7}-y\right).\frac{14}{5}=\frac{6}{5}\)

\(\frac{5}{7}-y=\frac{6}{5}\div\frac{14}{5}\)

\(\frac{5}{7}-y=\frac{3}{7}\)

\(y=\frac{5}{7}-\frac{3}{7}\)

\(y=\frac{2}{7}\)

Answer 3

\(\left(\frac{5}{7}-y\right)\) x \(\frac{14}{5}=\frac{7}{10}+\frac{1}{2}\)

\(\left(\frac{5}{7}-y\right)\) x \(\frac{14}{5}=\frac{6}{5}\)

\(\frac{5}{7}-y\)  = \(\frac{6}{5}:\frac{14}{5}\)

\(\frac{5}{7}-y\) = \(\frac{3}{7}\)

y= \(\frac{2}{7}\)

Answer 4

cảm ơn nha

Answer 5

\(\left(\frac{5}{7}-y\right)\times\frac{14}{5}=\frac{7}{10}-\frac{1}{2}\)

\(\left(\frac{5}{7}-y\right)\times\frac{14}{5}=\frac{6}{5}\)

\(\frac{5}{7}-y=\frac{6}{5}\div\frac{14}{5}\)

\(\frac{5}{7}-y=\frac{30}{70}\)

\(y=\frac{5}{7}-\frac{30}{70}\)

\(y=\frac{20}{70}=\frac{2}{7}\)

Answer 6

\(\left(\frac{5}{7}-y\right).\frac{14}{5}=\frac{7}{10}+\frac{1}{2}\)

\(\left(\frac{5}{7}-y\right).\frac{14}{5}=\frac{6}{5}\)

\(\frac{5}{7}-y=\frac{6}{5}:\frac{14}{5}\)

\(\Rightarrow\frac{5}{7}-y=\frac{3}{7}\)

\(y=\frac{5}{7}-\frac{3}{7}\)

\(y=\frac{2}{7}\)