a) \(\frac{2}{y+3}=\frac{3}{y+8}\Leftrightarrow\frac{y +3}{2}=\frac{y+8}{3}\)
\(=\frac{y+3-y-8}{2-3}=\frac{-5}{-1}=5\)
\(\Leftrightarrow\hept{\begin{cases}y+3=5.2\\y+8=5.3\end{cases}}\Leftrightarrow y=7\)
b) \(2018+\left|2018-x\right|\ge2020\)
\(\Leftrightarrow\left|2018-x\right|\ge2\Leftrightarrow x\le2016\)
\(\frac{2}{y}+3=\frac{3}{y}+8\)
=>\(3-8=\frac{2}{y}+\frac{3}{y}\)
=>\(-5=\frac{5}{y}\)
=>\(y=1\)
ko copy tth nhé, chỉ góp ý
\(b)\) \(2018+\left|2018-x\right|\ge2020\)\(\Leftrightarrow\)\(\left|2018-x\right|\ge2\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}2018-x\ge2\\2018-x\le-2\end{cases}\Leftrightarrow\orbr{\begin{cases}x\le2016\\x\ge2020\end{cases}}}\)
:))
