\(2016\times y+y=2017\)
\(2016\times y+1\times y=2017\)
\(y\times\left(2016+1\right)=2017\)
\(y\times2017=2017\)
\(y=2017:2017\)
\(y=1\)
Vậy y = 1
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2016 x y + y = 2017
2016 x y + y x 1 = 2017
y x (2016 +1) = 2017
y x 2017 = 2017
y = 2017 : 2017
y= 1
Vậy y =1
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