Question

tìm xϵz , biết :

a) 2x^2 - 3 = 29

b) -6x - (-7) = 25 

c) 46 - (x - 11 ) = -48

Answer 1

a/\(2\cdot x^2-3=29\)

\(2\cdot x^2=29+3=32\)

\(x^2=\frac{32}{2}=16\)

=> \(x=\sqrt{16}=4\)

b/\(\left(-6\right)x-\left(-7\right)=25\)

\(\left(-6\right)x+7=25\)

\(\left(-6\right)x=25-7=18\)

\(x=\frac{18}{-6}=-3\)

c/ \(46-\left(x-11\right)=-48\)

\(46-x+11=-48\)

\(x=46-\left[\left(-48\right)-11\right]=105\)

Answer 2

a) 2x^2 -3= 29

   2x^2     = 32

     x^2     = 16

     x        = +4 ; -4

b) -6x - (-7) =25

    -6x +7    =25

    -6x         = 18

       x         = -3

c) 46 - (x-11) = -48

    46 -x +11 = -48

    46 -x        = -59

         x         = 105

Answer 3

a/\(2x^2-3=29\)

\(2x^2=29+3=32\)

\(x^2=\frac{32}{2}=16\)

\(x=\sqrt{16}=4\)

b/\(\left(-6\right)x-\left(-7\right)=25\)

\(\left(-6\right)x+7=25\)

\(\left(-6\right)x=25-7=18\)

\(x=\frac{18}{-6}=-3\)

c/\(46-\left(x-11\right)=-48\)

\(46-x+11=-48\)

\(x=46-\left[\left(-48\right)-11\right]=105\)

Answer 4

thieu cau a roi VICTOR_Huỳnh Châu Giang

Answer 5

Bổ sung câu a nghen!

\(x\in\left\{-4;4\right\}\)