Question

tim x,ybiet

a) x/4=25/x

b)y^2/3=12/1

Answer 1

a) Ta có: \(\frac{x}{4}=\frac{25}{x}\Rightarrow x.x=25.4\Rightarrow x^2=100\Rightarrow x=\pm10\)

Vậy x = {10;-10}

b) \(\frac{y^2}{3}=\frac{12}{1}\Rightarrow y^2=12.3\Rightarrow y^2=36\Rightarrow y=\pm6\)

Vậy x = {6;-6}

Answer 2

     \(\frac{x}{4}=\frac{25}{x}\)

\(\Leftrightarrow\)\(x\times x=25\times4\)

\(\Leftrightarrow\)\(x\times x=100=10\times10\)

\(\Leftrightarrow\)\(x=10\)

P/s:  vì tiểu hok chưa học số nguyên âm nên chỉ có  x = 10   thôi nhé

Answer 3

a) Ta có :

\(\frac{x}{4}=\frac{25}{x}\)

\(\Leftrightarrow\)\(x.x=4.25\)

\(\Leftrightarrow\)\(x^2=100\)

\(\Leftrightarrow\)\(x=\sqrt{100}\)

\(\Leftrightarrow\)\(x=10\)

b) Ta có :

\(\frac{y^2}{3}=\frac{12}{1}\)

\(\Leftrightarrow\)\(y^2=12.3\)

\(\Leftrightarrow\)\(y^2=36\)

\(\Leftrightarrow\)\(y=\sqrt{36}\)

\(\Leftrightarrow\)\(y=6\)

Answer 4

thankyou tất cả các bạn