Question

tìm xy biết

xy+2x-y=2

giải hộ mk vs

Answer 1

\(xy+2x-y=2\)

\(\left(xy+2x\right)-y-2=0\)

\(x\left(y+2\right)-\left(y+2\right)=0\)

\(\left(y+2\right)\left(x-1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}y+2=0\\x-1=0\end{cases}\Rightarrow\orbr{\begin{cases}y=-2\\x=1\end{cases}}}\)

Answer 2

\(xy+2x-y=2\\ \left(xy+2x\right)-y-2=0\\ x\left(y+2\right)-\left(y+2\right)=0\\ \left(y+2\right)\left(x-1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}y+2=0\\x-1=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}y=-2\\x=1\end{cases}}\)